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3(x-2)^2-5=0
We move all terms containing x to the left, all other terms to the right
3(x-2)^2=5
| (3y+2)^2+36=0 | | d/0.4=1 | | M1=3x-17M2=x+1 | | (x^2)+1.5=0 | | -2x+3.2=2.8 | | -6x-4=-8x-8 | | 3y=8-12/4+2 | | 9(x+2)-4=5x+4(3+x) | | 40p-4.50=112 | | 0=(x^2)+1.5 | | 8/9y=8+4/9y | | f(3)=-2/3+3 | | a/12=2 | | 2(a-1)=2a-3/5 | | 12x+8=10x+5 | | 9j-17=14j+13-3j | | 6-14=z/6 | | M1=3x-17• | | 2+14d=8+12d | | -8z+12=-5z | | 10+8m=2m+8m-8 | | -3.50x-4=-38.125 | | 12x+8=10x+3 | | -8s=-6-10s | | 167.2=-5.6+7.2x | | 2x2-3x=x2+10 | | -3-t+7t=-3-2t | | 6.8x-30.8=30.4 | | -7.24q=17,014 | | 4.1=-4y+16.9 | | 2c^2+19c+24=0 | | -17+2=5(x+2) |